9/2/2023 0 Comments Epoch time calc![]() ![]() Of course, then you can also do: print localtime(time) -> epoch Īnd do without all the fuss of converting back and forth. Note - Time::Piece overloads localtime so you can actually use it (fairly) transparently. Print localtime(time) -> strftime ( "%Y-%m-%d %H:%M:%S" ) You would probably be better off instead using Time::Piece and strftime to get a fixed format: This is the usual format used in American dates. When both the month and the date are specified in the date as numbers they are always parsed assuming that the month number comes before the date. That's probably why str2time is doing odd things - because it makes certain assumptions about formats that don't always apply. If you do it in a scalar context, it returns a string denoting the time: print "".localtime(time) īut note - that might vary somewhat depending on your current locale. (Which you can use without needing to parse). (In days, so you'll have to multiply up).īut if you really want to take the time and convert it back again - you'll need to look at how localtime(time) returns the result.īecause localtime is being evaluated in a list context, and so returning an array of values. Or perhaps better yet -M which tells you how long ago a file was modified. Put (1 + floor ( (year - 4 * floor (year / 4) + 2) / 3) ) into N3įunction floor pNumber - LiveCode has no built-in floor() functionĮnd floor T-SQL (Transact-SQL) SELECT DATEPART(DAYOFYEAR, SYSDATETIME()) or SELECT datediff(day,CAST(datepart(year,getdate()) AS CHAR(4)) + '-01-01',getdate()+1)ĪS number_of_today Go (golang) day := time.Now().You're doing something bizarre here - localtime(time) takes - the epoch time ( time) and converts it to a string. Put currentDay - firstDayofYear into totalSecondsĪnswer the round of (totalSeconds / (60*60*24)) + 1 -display total days in dialog boxĬonvert currentDate to dateItems -list of date elements separated by commas Put "January 1," & the last word of the long date into firstDayofYear -append current yearĬonvert firstDayofYear to seconds - from to first day of this yearĬonvert currentDay to seconds - from GMT to today Write-Host $DayOfYear LiveCode on mouseUp Puts time.yday Powershell $DayOfYear = (Get-Date).DayofYear Java LocalDate.now().getDayOfYear() Unix/Linux date +%j ColdFusion #dayofyear(now())# Objective C int currentDay ĭateFormatter = init] ĬurrentDay = intValue] Ĭ# int iDayOfYear = R format(Sys.Date(), "%j") Ruby time = Time.new Var onejan = new Date(this.getFullYear(),0,1) Or add a 'Day of Year' method to the date object: Select to_char(to_date('','YYYY-MM-DD'), 'DDD') from dual Delphi using DateUtils, SysUtils ĭayOfTheYear(Date) Microsoft Access DatePart("y", Now()) Visual Basic (VB.NET) Dim dayOfYear As Integer = JavaScript Hi All, In our code we are using below code to calculate the UNIX Epoch Time from the time stamp present in the file. SELECT DAYOFYEAR('') Oracle select to_char(sysdate, 'DDD') from dual Disclaimer: This calculator only predicts an estimate of rewards. Now you can do more than holding see how much rewards you can possibly earn by staking ada. The more ada you stake, the more rewards you can earn. MySQL SELECT DAYOFYEAR(NOW())ĭay number between 1 and 366. Staking ada provides ada holders with rewards - in addition to the potential market price gains. Replace time with other epochs for other days. My $day_of_year = POSIX::strftime("%j", time) ![]() ![]() You can use an epoch to find other day numbers:ĭate("z") starts counting from 0 (0 through 365)!ĭay_of_year = datetime.now().timetuple().tm_yday PERL correct/x.shape 0 Instead you should divide it by number of observations in each epoch i.e. LibreOffice Calc: =ROUNDDOWN(DAYS(NOW(),DATE(YEAR(NOW()),1,1))) + 1 PHP $dayNumber = date("z") + 1 In your code when you are calculating the accuracy you are dividing Total Correct Observations in one epoch by total observations which is incorrect. (Your date format (1-1-year) may be different) ![]() =A1-DATE(YEAR(A1),1,0) Google Docs Spreadsheet =DATEDIF(CONCAT("1-1-" year(now())) today() "D")+1Ĭalculates the difference between Jan 1 and today (=days past) then add 1 for today's daynumber. Or, for any date entered in cell A1, calculate the corresponding day-number in that date’s year: Calculate today's day-number, starting from the day before Jan 1, so that Jan 1 is day 1. ![]()
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